The simplified value of following

\(\left( {\frac{3}{{15}}{a^5}{b^6}{c^3} \times \frac{5}{9}a{b^5}{c^4}} \right) \div \frac{{10}}{{27}}{a^2}b{c^3}\)

This question was previously asked in

UPSSSC Lower PCS Prelims Official Paper 1 (Held On : 15 July 2018)

- \(\frac{{9{a^2}b{c^4}}}{{10}}\)
- \(\frac{{3a{b^4}{c^3}}}{{10}}\)
- \(\frac{{3{a^4}{b^{10}}{c^4}}}{{10}}\)
- \(\frac{{1{a^4}{b^4}{c^4}}}{{10}}\)

Option 3 : \(\frac{{3{a^4}{b^{10}}{c^4}}}{{10}}\)

Ace your Algebra preparations for Linear Equation in 2 or more Variables with us and master Quantitative Aptitude for your exams. Learn today!

**Calculation**

15(a^{6}b^{11}c^{7})/135/10(a^{2}bc^{3})/27

⇒ 15 × 27(a^{4}b^{10}c^{4})/(135 × 10)

**⇒**** 3(a ^{4}b^{10}c^{4})/10**

India’s **#1 Learning** Platform

Start Complete Exam Preparation

Daily Live MasterClasses

Practice Question Bank

Mock Tests & Quizzes

Trusted by 2,29,57,357+ Students

Testbook Edu Solutions Pvt. Ltd.

1st & 2nd Floor, Zion Building,

Plot No. 273, Sector 10, Kharghar,

Navi Mumbai - 410210

[email protected]
Plot No. 273, Sector 10, Kharghar,

Navi Mumbai - 410210

Toll Free:1800 833 0800

Office Hours: 10 AM to 7 PM (all 7 days)